| 개발자: | Vineeta Garg (9) | ||
| 가격: | 무료 | ||
| 순위: | 0 | ||
| 리뷰: | 0 리뷰 작성 | ||
| 목록: | 0 + 0 | ||
| 포인트: | 0 + 0 ¡ | ||
| Google Play | |||
기술
2. It is specially made for children who are novice at Python coding. Students who are studying AI, CS and IP subjects will definitely be benefitted by this game. The game covers the topic “Conditional and Looping Statements” in Python.
3. There are two doors in a mystery house. The player has to open both the doors to get the gold. To open the doors, he needs to crack the Python code. On the first door there are eight cards and on the second door there are 12 cards laid out in a grid with face down.
4. On each turn, the player will first turn one card over and then the second.
5. If the two cards match (Python code written on one card should match the output written on the second card) the player scores one point and if they do not match, the cards are turned back over.
6. The time duration for finding all the matching cards present on the first door is 1 minute and on the second door in 3 minutes.
7. The player will win if he is able to open both the doors.
8. This game will certainly help players to improve their performance on the topic “Conditional and Looping Statements”.
스크린샷







새로운 기능
- 버전: 0.6
- 업데이트:
- This a single player mystery game and has two levels. The game covers the topic “Conditional and Looping Statements” in Python. It has been specially made for children who are novice at Python coding. Students who are studying AI, CS and IP subjects will definitely be benefitted by this game. This app has been released under the Creative Commons CC BY-NC license as an Open Educational Resource (OER)
가격
- 오늘: 무료
- 최소: 무료
- 최대: 무료
가격 추적
개발자
- Vineeta Garg
- 플랫폼: Android 앱 (5) Android 게임 (4)
- 목록: 0 + 0
- 포인트: 0 + 0 ¡
- 순위: 0
- 리뷰: 0
- 할인: 0
- 동영상: 3
- RSS: 구독
포인트
0 ☹️
순위
0 ☹️
목록
0 ☹️
리뷰
첫 번째 리뷰를 남겨보세요 🌟
추가 정보
주소록
- 웹사이트:
http://www.python4me.com
- 🌟 공유하기
- Google Play
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