KIDBEAR
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- 平台: iOS 遊戲 (7)
- 排名: 0
- 總計: 7
- 清單: 0 + 1
- 評測: 0
- 免費: 7
- 點數: ¡ 0 + 11,305
- 影片: 0
- 付費: 0
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- Merge Plus
- iOS 遊戲: 解謎 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 10,267 (4.6) 版本: 3.6 It's a simple and interesting number game. The goal of the game is to get bigger numbers. How to play You have 5 hand cards in the beginning, Drag the first card in the Hand Card Area ... ⥯
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- Merge X
- iOS 遊戲: 解謎 由: KIDBEAR
- 免費
- 清單: 0 + 1 排名: 0 評測: 0
- 點數: 0 + 25 (4.6) 版本: 1.9 How to play: Tap any number block on the chessboard to increase its value by 1 or 2. Three adjacent blocks can be combined into a block of larger number: Three blocks of 1 can be ... ⥯
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- Fish Pop Mania
- iOS 遊戲: 解謎 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 376 (4.6) 版本: 1.8 Fish Pop Mania is a challenging puzzle game. In the deep ocean, a flock of small fish are trapped in bubbles. Tap adjacent bubbles of the same color, and they will explode. The more ... ⥯
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- Tens Up-Merge Blocks
- iOS 遊戲: 休閒 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 7 (4.1) 版本: 1.5.2 It'a an easy and simple game which merge the bigger numuber. The target is: merge the falling numbers and the basic numbers on the board.The more you merge,the bigger number you will ... ⥯
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- aazz
- iOS 遊戲: 冒險 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 597 (4.6) 版本: 1.3 Aazz is a very simple game which with spell that cannot stop playing. tap to insert ball, don't let the small balls collision. It's as simple as that. The game features: Tap to play - ... ⥯
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- Zombie Rush！
- iOS 遊戲: 賽車遊戲 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 33 (4.5) 版本: 1.4 In this extremely tense and stimulating game, your only purpose is to survive. You need to escape the clutches of zombies, and use the steering angle to guide them to harm each other. ... ⥯
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- 1223
- iOS 遊戲: 解謎 由: KIDBEAR
- 免費
- 清單: 0 + 0 排名: 0 評測: 0
- 點數: 0 + 0 版本: 1.0 welcome to 1223,this is a simple game,you will have much fun in the game. Move the number,you can move one space once time,three or more than three of the same number get in line,then ... ⥯
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